you crossed F1 hybrids that were heterozygous for both genes to generate the F2
ID: 3519679 • Letter: Y
Question
you crossed F1 hybrids that were heterozygous for both genes to generate the F2 generation. The crosses to make the F1 flies was done behind the scenes. se is the mutant allele for the sepia eye mutation and se+ is the wildtype red eye allele, ap is the apterous mutation and ap+ is the wild type wings allele. bw is the mutant allele for brown eyes and bw+ is the wildtype red eye mutation, and finally vg is the vestigial wings mutation and vg+ is the wild type wings allele. The wildtype allele is dominant in all cases (this may not strictly be true but from our phenotypic perspective it is). In one cross this was red (se+) versus sepia eye (se) and wings (ap+) versus apterous (ap), and in the other cross this was red (bw+) versus brown (bw) and wings (vg+) versus vestigial (vg) The crosses we did behind the scenes are below: P: se + se+ ap+ap+, se se ap ap F1: se"se ap+ap and You then took the F1s and set up the crosses below: FI: setse aptapx setse ap+ap The numbers in the spreadsheet are the F2 generation. Your goal is to figure out whether our data matches Mendelian expectations for a dihybrid cross or not. And if not, discuss why this might be.Explanation / Answer
this data follows mendelian expectations for dihybrid cross.
mendelian law for dihybrid cross is Mendel's Law of Independent Assortment.
according to this law,the genes do not influence each other in sorting of allels into gametes.so every possible copmbination can occur as in this data every possible combination has occured.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.