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2. (7 points) In a particular species of plant, flower color can be light-blue,

ID: 3510517 • Letter: 2

Question

2. (7 points) In a particular species of plant, flower color can be light-blue, turquoise, and white. A series of crosses was done to determine how flower color is inherited in this plant. The table below shows the phenotypes of the P generation to the left and the phenotypes of the F1 generation to the right. The number of offspring with each phenotype is also provided. Cross# P generation phenotypes F1 generation phenotypes turquoise x turquoise light blue x light blue turquoise x white white x white all turquoise 60 light blue, 29 turquoise, 31 white all light blue all white 2 ONE gene controls flower color in this plant. Flower color is EITHER an example of incomplete dominance OR an example of multiple alleles of a single gene. To correctly answer the following questions, you must first determine whether this is incomplete dominance or multiple alleles. Once you have made your determination, create appropriate symbols for each allele of the flower color gene. Use the letter C to symbolize the gene and use superscripts (C' for example) to designate the alleles of this gene. In the space below, indicate all possible homozygous genotypes and the phenotype produced by each of these genotypes. (For example: C'C produces turquoise flowers) Draw a Punnett square of cross 2 in the space below, showing the potential genotypes of the offspring of the cross. If a plant with turquoise flowers were crossed to one with light blue flowers, what would be the phenotypes of the offspring?

Explanation / Answer

Types of inheritence:

1st cross shows: Complete dominance

2nd cross shows: Multiple allelism

3rd cross shows: Incomplete dominance

4th cross shows: dominance

from above crosses and type of inheritance we can predict that in case of multiple allelism torqoius (CBCB)> CTCT >CwCw

Possible genotypes and phenotypes

CTCT = Torquious flower

CBCB = Light blue color

CwCw= White color

CTCB = Light blue color

CBCw = Light blue color

CTCT *  CBCB

CTCB (all blue color)

CT CB CB CTCB (light blue) CTCw(torquious blue) Cw CBCB(light blue) CBCw(white )
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