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184 BUSQOM 1070 SEC1030 OPERATIONS MANAGEMENT omework: HW-CH07s core: 0 of 1 pt

ID: 350554 • Letter: 1

Question

184 BUSQOM 1070 SEC1030 OPERATIONS MANAGEMENT omework: HW-CH07s core: 0 of 1 pt roblem S7.11 The three-station work cell ilustrated in the figure below has a product that must go through one of the two machines at station 1 (they are parallel) before Megan Shearson 3/18/18 7:10 PM Sav 2 of 3(0 te) Hw Score: 0%, 0 of 3 ; Question Help proceeding to station 2 Capacity: 20 units/hr Station 1 Machine A Station 2Station 3 Capacity: 10 units/hr 3 units/hr Station1 Machine B Capacity: Capacity: 20 units/hr a) The bottleneck time of the system is minutes per unit (enter your response as a whole number)

Explanation / Answer

Station1 = 60/20 = 3min/unit (for both machine A and B)

STATION2= 60/10 = 6min/unit

Station 3 = 60/3 =20min/unit

Bottleneck operation is station 3 at 20 min/unit

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