needed A company manufactures hair dryers. It buys some of the components, but i
ID: 348542 • Letter: N
Question
needed
A company manufactures hair dryers. It buys some of the components, but it makes the heating element, which it can produce at the rate of 830 per day. Hair dryers are assembled daily, 248 days a year, at a rate of 315 per day. Because of the disparity between the production and usage rates, the heating elements are periodically produced in batches of 2,300 units.
a. Approximately how many batches of heating elements are produced annually? (Round your answer to 2 decimal places.)
Number of batches
b. If production on a batch begins when there is no inventory of heating elements on hand, how much inventory will be on hand 4 days later?
Number of inventory
c.What is the average inventory of elements, assuming each production cycle begins when there are none on hand? (Do not round intermediate calculations. Round your answer to the nearest whole number.)
Average inventory
d. The same equipment that is used to make the heating elements could also be used to make a component for another of the firm’s products. That job would require 6 days, including setup. Setup time for making a batch of the heating elements is a half day. Is there enough time to do this job between production of batches of heating elements?
Yes
No
Problem 14-7
Compute the takt time for a system where the total time per shift is 370 minutes, there is one shift, and workers are given 2 13-minute breaks and 30 minutes for lunch. Daily demand is 353 units. (Round your answer to 2 decimal places.)
Takt time minutes per cycle
Problem 14-8
What cycle time would match capacity and demand if demand is 173 units a day, there are 2 shift(s) of 458 minutes each, and workers are given three 35 minute breaks during each shift, one of which is for lunch or dinner? (Round your answer to 2 decimal places.)
Cycle time minutes per cycle
Explanation / Answer
Each hair dryer requires 1 heating element
Therefore , number of heating elements required annually =315 / day x 248 days
Batch size of production for heating elements = 2300
Number of batches of heating elements produced annually = 315 x 248 / 2300 = 33.96
NUMBER OF BATCHES = 33.96
= Daily production rate – Daily usage rate
= 830 – 315
= 515
Therefore , quantum of inventory on hand 4 days later = 515 / day x 4 days = 2060
NUMBER OF INVENTORY = 2060
Minimum inventory of heating elements = 0
Average inventory = ( Maximum inventory + Minimum inventory )/ 2 = 1426/2 = 713
AVERAGE INVNETORY = 713
Since set up time of heating element per batch = 0.5 day
Total set up time required in a year = 0.5 x 33.96 days = 16.98 days
Number of heating elements required in a year = 315 / day x 248 days = 78120
At production rateof 830 per day , number of days of production ( without set up time ) required for heating element = 78120 /830 = 94.12 days
Therefore, total time required in a year for heating elements
= Actual production time + Set up time
= 94.12 + 16.98
= 111.10 days
Therefore, spare time available annually to produce other components = 248 days ( available time in a year ) – 111.10 ( total time required for heating elements ) = 136.9 days
However, time required for the other job is 6 days which is less than 136.9 days of spare time .. Therefore, there is enough time to do this job between production of batches of heating elements
ANSWER : YES
Answer to problem 14.7 :
Net available time in a day = 370 minutes – 2 x 13 minutes break – 30 minutes lunch time = 370 – 26 – 30 = 314 minutes
Daily demand = 353 units
Therefore , takt time = Net available time / Daily demand = 314/ 353 minutes = 0.889 ( 0.89 rounded to 2 decimal places )
TAKT TIME = 0.89 MINUTES PER CYCLE
Answer to problem 14.8 :
Net available time in a shift = 458 minutes – 3 breaks x 35 minutes/ break = 458 minutes – 105 minutes = 353 minutes
Net available time in a day = Net available time in 2 shifts = 2 x 353 minutes = 706 minutes
Daly demand = 173 units
Cycle time = Net available time in a day / Daily demand = 706/ 173 = 4.08 minutes per cycle
CYCLE TIME = 4.08 MINUTES PER CYCLE
NUMBER OF BATCHES = 33.96
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