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water retrieval ability in the Griffon [8.0 points) Consider the following infor

ID: 3478482 • Letter: W

Question

water retrieval ability in the Griffon [8.0 points) Consider the following information on The performance of the dogs is scored on a continuous scale from 0 (dog will not enter water to retrieve the bird) to 4 (dog swims directly to the bird, retrieves, and delivers to the handler). Parameter Average Gene combination value variance Permanent environmental variance Temporary environmental variance Total phenotypic variance Value 3.4 pt 0.030 pt 0.100 pt 0.170 pt 0.576pt' [3.0 points] In a single trial, one dog (dog A) scores a 3.9 while another dog (dog B) scores a 2.4. What are the estimated breeding values (EBV) for water retrieval ability for these two dogs?

Explanation / Answer

We have been provided-

The additive gene variance Va = 0.03 pt2

Total phenotypic variance Vp = 0.576 pt2

Through this calculate narrow sense heritability ‘h’ by the following formula=

h2 = Va ÷ Vp

h2 =0.03 ÷ 0.576

h2 = 0.052

h = h2

h= 0.052

h= 0.228

The Estimated breeding value E = h2 × Ps

Here Ps is the phenotypic superiority, which calculates by following formula

Ps = (PA ~ PB) ÷ Pk

Here Pk is the average score, PA and PB are the scores of two individuals.

PA = 3.9; PB = 2.4; Pk = 3.4

So,

Ps = (3.9 ~ 2.4) ÷ 3.4

Ps = 0.44

Now,

Estimated breeding value E = h2 × Ps

E =0.052 × 0.44

E= 0.023