You have two solutions: A: 0.72g glucose to 1.0L water (glucose has a molecular

Question

You have two solutions: A: 0.72g glucose to 1.0L water (glucose has a molecular weight of 180g/mol B: 0.117g NaCl to 1.0L water (NaCl has a molecular weight of 58.5 g/mol) Calculate molality and osmolality of each solution. a. A: molality = 4mmolal: osmolality = 4mOsm: B: molality = 4mmolal: osmolality = 2mOsm b. A: molality = 4mmolal: osmolality = 4mOsm: B: molality = 2mmolal: osmolality = 2mOsm: c. A: molality = 0.004mmolal: osmolality = 4 mOsm: B: molality = 0.002mmolal: osmolality = 4mOsm d. A: molality = 4mmolal: osmolality = 4mOsm: B: molality = 4mmolal: osmolality = 4mOsm e. A: molality = 4mmolal: osmolality = 4mOsm: B: molality = 2mmolal: osmolality = 4mOsm

Explanation / Answer

answer is option b

molarity formula :

M = weight/molecular weight * 1000 / voume in ml

For A

M = 0.72/180 * 1000/1000 = 0.004

i.e., 4mM

similarly For B

2mM

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