The following two-way contingency table gives the breakdown of the population in

Question

The following two-way contingency table gives the breakdown of the population in a particular locale according to party affiliation (A, B, C, or None) and opinion on a bond issue:

A person is selected at random. Find the probability of each of the following events.

A.The person is affiliated with party B.

B.The person is affiliated with some party.

C.The person is in favor of the bond issue.

D.The person has no party affiliation and is undecided about the bond issue.

Affiliation Opinion Favors Opposes Undecided A 0.12 0.09 0.07 B 0.16 0.12 0.14 C 0.04 0.03 0.06 None 0.08 0.06 0.03

Explanation / Answer

a)

P(B) = 0.16 + 0.12+0.14 = 0.42 [answer]

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b)

P(A or B or C) = sum of the first three rows = 0.83 [answer]

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c)

P(favor) = 0.12 + 0.16 + 0.04 + 0.08 = 0.40 [answer]

***********

d)

looking at the table,

P(no party and undecided) = 0.03 [answer]

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