Suppose that you roll a pair of 24-sided dice (with the sides numbered 1-16) a t

Question

Suppose that you roll a pair of 24-sided dice (with the sides numbered 1-16) a total of 200 times. What is the probability that you will get a sum of 3 at least two times? Suppose that you roll a pair of 24-sided dice (with the sides numbered 1-16) a total of 200 times. What is the probability that you will get a sum of 3 at least two times? Suppose that you roll a pair of 24-sided dice (with the sides numbered 1-16) a total of 200 times. What is the probability that you will get a sum of 3 at least two times?

Explanation / Answer

If you have a pair of dice with 24 faces, you can roll a variety of sums. If the faces of the dice are labeled with the numbers 1 through 24, the highest sum you can roll is 48, and the lowest you can roll is 2. But as in here the dice are labeled with the numbers 1 through 16, the highest sum you can roll is 16+16= 32 and the lowest sum is nothing 0+0=0, because each die has 8 sides without numbers ( from 17 to 24 ) that we have asigned the number of zero "empty side".

if a pair of 24-sided dice are rolled (with the sides numbered 1-24),the total number of ways of throwing a pair of D24 dice is 24*24 = 576, and the probability of getting a sum of three (3) is 2/576 , like this:

(die 1, die 2) = (1, 2); (2,1)

in our case we have this:

(die 1, die 2) = (1, 2); (2,1) ; (3, 0); (0,3), it means that in this case the probability of  getting a sum of three (3) is 4/576. We have to take into account that the dice are rolled a total of 200 times.

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