The following sample information shows the number of defective units produced on

Question

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

At the .05 significance level, can we conclude there are more defects produced on the day shift?

The null and alternate hypotheses are:
   H0 : ?d ? 0 H1 : ?d > 0   

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

Day       1 2 3 4   Day shift 11     10     14    17      Afternoon shift 8     11     12    15  

Explanation / Answer

(1) The degree of freedom =n-1=4-1=3

Given a=0.05, the critical value is t(0.05, df=3)=2.353 (from student t table)

Reject H0 if t >2.35

------------------------------------------------------------------------------------------------------------------

(2)

test statistic is

t= mean difference/(s/vn)

=1.732

13.000 mean Day shift 11.500 mean Aternoon shift 1.500 mean difference (Day shift - Aternoon shift) 1.732 std. dev. 0.866 std. error 4 n 3 df

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.