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A survey is being planned to determine the mean amount of time corporation execu

ID: 3431157 • Letter: A

Question

A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 13 hours, with a standard deviation of 2.0 hours. It is desired to estimate the mean viewing time within one-quarter hour. The 90 percent level of confidence is to be used.

A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 13 hours, with a standard deviation of 2.0 hours. It is desired to estimate the mean viewing time within one-quarter hour. The 90 percent level of confidence is to be used.

  

Explanation / Answer

Given a=1-0.9=0.1, Z(0.05) = 1.645 (from standard normal table)

So n=(Z*s/E)^2

=(1.645*2/0.25)^2

=173.1856

Take n=174

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