#4 and #5 A snail is crawling in a straight line and at a constant rate across t
ID: 3425768 • Letter: #
Question
#4 and #5
Explanation / Answer
4) First point ( -2, 4)
second point (3,3)
slope w.r.t time = deltax/detla time= (3- (-2))/1 = 5 units/min
So, x(t) = 5t
deltax/detla time= ( 3-4)/(1) = -1 units/min
y(t) = -t
Position two minutes (x, y) before it was at (-2, 4)
So, delta(x)/delta(t) = 5units/min
So, (-2 -x)/2 = 5---> -2-x = 10
x = -12
delta(y)/delta(t) = -1units/min
(4 -y)/2 =-1 ---> 4-y =-2
y = 6
So, it was at ( -12 ,6)
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