Graphically, the solutions are just the points on the line 4x + 2y-4: 4 -3 -2 2.
ID: 3409294 • Letter: G
Question
Graphically, the solutions are just the points on the line 4x + 2y-4: 4 -3 -2 2. Enter three particular solutions and then the general solution of the equation 2x+3y =-4. Enter particular solutions in the form (x,y). Example: (5,-8) First particular solution: (-2,0) Second particular solution: (1,-2) Check Clear Free Hint Check Clear Free Hint Check Clear Free Hint Third particular solution: (-1/2,-1) Enter general solution as (x,y(x)) where x) is a function of x. General solution: Check ClearFree HintExplanation / Answer
2, The graph is only illustrative. The graph only illustrates that the solution of the equation will lie on the line. The paricular solutions of the equation 2x + 3y = -4 can be obtained by substituting arbitrary values of x like -2, 1, -1/2 and determining the corresponding values of y from the equation:
i. When x = - 2, we have 2(- 2)+3y = - 4or, -4 + 3y = -4 or, 3y = 0 so that y = 0. Thus one paricular solution is (-2,0)
ii. When x = 1, we have 2(1)+3y = - 4 or, 2 + 3y = -4 or, 3y = -6 so that y = -2 Thus 2nd paricular solution is (1, -2)
iii. When x = -1/2, we have 2(-1/2)+3y = - 4 or, -1 + 3y = -4 or, 3y = -3 so that y = -1Thus 3rd paricular solution is ( ( - 1/2, - 1).
The general solution can be found by seperating the terms of x and y. We have 2x + 3y = -4 or, 3y = - 4 - 2x or, y = - 4/3 - 2/3x. Thus, the general solution is ( x, - 4/3 - 2/3x)
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