5 of 7 complete Ex. Score: 0 of 1 pt HW Score: 57.14% (4 of 7 pts) | 8.3.4 Suppo
ID: 3398917 • Letter: 5
Question
5 of 7 complete Ex. Score: 0 of 1 pt HW Score: 57.14% (4 of 7 pts) | 8.3.4 Suppose a certain home plate on a line joining home plate and second base. (a) How far is it from the pitching rubber to first base? (b) How far is it from the pitching rubber to second base? (e) If a pitcher faces home plate, through what angle does he need to turn to face first bass? baseball diamond is a square 80 feet on a side. The pitching rubber is located 55.5 feet from e) If a pitcher faces home plate, through what angle does he need to turn to face first base? (a) The distance from the pitching rubber to first base is about feet. (Round to two decimal places as needed.)
Explanation / Answer
Distance travelled by ship from San Juan in the direction of 39 deg = 18*14 = 252 nautical miles
In the triangle one side = 600 nautical miles
Applying cosine rule to find the distnace from middel path to Barbados be x:
b) x^2 = 252^2 +600^2 -2*252*600cos39
x = 434.16 nautical miles
Time taken to travel this distnace to Barbados = 434.16/18 = 24.12 hrs
a) To find angle of diversion use sine rule:
434.16/sin39 = 600/siny
siny =0.869
y = 60.42 deg
So, the angle through which ship diverts to reach Barbados = 180 -60.42 = 119.57 deg
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