A survey of 300 students selected randomly on a large university campus. they ar

Question

A survey of 300 students selected randomly on a large university campus. they are us of the use a laptop in class to take notes. suppose that based on the survey 105 of the 300 students responded yet. if P equals .35 and the standard error of the sample proportion is .028 what is the approximate 95% confidence interval for for the true proportion P by taking 2SEs from the sample portion is? please show how confidence interval is found. A survey of 300 students selected randomly on a large university campus. they are us of the use a laptop in class to take notes. suppose that based on the survey 105 of the 300 students responded yet. if P equals .35 and the standard error of the sample proportion is .028 what is the approximate 95% confidence interval for for the true proportion P by taking 2SEs from the sample portion is? please show how confidence interval is found. A survey of 300 students selected randomly on a large university campus. they are us of the use a laptop in class to take notes. suppose that based on the survey 105 of the 300 students responded yet. if P equals .35 and the standard error of the sample proportion is .028 what is the approximate 95% confidence interval for for the true proportion P by taking 2SEs from the sample portion is? please show how confidence interval is found.

Explanation / Answer

As

p^ = 0.35

SE = 0.028

Then the approximate 95% confidence interval is obtained by adding and subtracting 2SE from the mean proportion. Hence,

lower bound = 0.35 - 2*0.028 = 0.294

upper bound = 0.35 + 2*0.028 = 0.406

Thus, the confidence interval is

(0.294, 0.406) [ANSWER]

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