tp/elearing 09 ketes cdu/ webappo/ sesment/takec/bunchyp courme anuesmemt earni
ID: 3391624 • Letter: T
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tp/elearing 09 ketes cdu/ webappo/ sesment/takec/bunchyp courme anuesmemt earni Sol 010 ake/launchjsp?course assessment jid 1420253, 1&course; id- 493375185, 1acontent id- 1644614 16se QUESTION 16 A doctor claims that the standard deviation of systolic blood standard deviation of systolic blood pressure is 12 mmblg A random sample of 24 parierts found a standard deviation of 14 mmig Assune the vatiable s omalyued = 0 01, what are the critical X2 values? - A) 9.262 and 44 181 B) 13.091 and 35.172 o C) 13.848 and 36 415 O D) 11.524 and 44 314 pressure is 12 mmHg A random sample tt 24 patients fourd·strdirt de ition d'aning AssumRe vaiabl·on-dili i A. 4- QUESTION 17 A lumber mill is tested for consistency by measuring the variance 0.006 square inches, is there e 4 points bard thickness The target accuracy is a variance of 0 0035 square inches or less. If 24 measurements are made and thv of board hickness The taget accuracy is a variance of A) No, since the X2 test value 39 43 is less than the critical value 41 638 B ) Yes, since the X2 test value 8 22 is less than the citical value 41 638 - C) No, since the X2 test value 39 43 is less than the citical value 42 980 D) Yes, since the X2 test value 8 22 is less than the cmcal value 42 900 i points QUESTION 18 150 ata-ogg wouldExplanation / Answer
16.
As alpha = 0.01, and df = n - 1 = 23, then the critical values, by table/technology, are
chi^2(crit) = 9.260424776 and 44.18127525 [ANSWER, A]
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17.
Formulating the null and alternative hypotheses,
Ho: sigma <= 0.059160798
Ha: sigma > 0.059160798
As we can see, this is a right tailed test.
Thus, getting the critical chi^2, as alpha = 0.01 ,
alpha = 0.01
df = N - 1 = 23
chi^2 (crit) = 41.63839812
Getting the test statistic, as
s = sample standard deviation = 0.077459667
sigmao = hypothesized standard deviation = 0.059160798
n = sample size = 24
Thus, chi^2 = (N - 1)(s/sigmao)^2 = 39.42857143
As chi^2 < chi^2(crit), then we FAIL TO REJECT THE NULL HYPOTHESIS.
Hence, it is OPTION C. [ANSWER]
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