A random sample of n 1 = 10 regions in New England gave the following violent cr

Question

A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population).

x1: New England Crime Rate

Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population).

x2: Rocky Mountain Crime Rate

Assume that the crime rate distribution is approximately normal in both regions.

(a) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.)

(b) Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use = 0.10.

What is the level of significance?

(c) What is the value of the sample test statistic? (Test the difference 1 2. Round your answer to three decimal places.)


(d) Find (or estimate) the P-value. (Round your answer to four decimal places.)

3.5 3.6 3.9 3.8 3.3 4.1 1.8 4.8 2.9 3.1

Explanation / Answer

H0: mu1 = mu2

Ha: mu1>mu2

Right tailed test

t = 0.9955
  df = 20
  standard error of difference = 0.372

P value equals 0.1657

As p >alpha, acceptnull hypothesis that two are equal.

x1 3.5 3.6 3.9 3.8 3.3 4.1 1.8 4.8 2.9 3.1 3.48 0.799722 Mean Std dev x2 3.9 4.1 4.4 5.2 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 3.85 0.916019

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