John Isaac Inc., a designer and installer of industrial signs, employs 60 people
ID: 3387750 • Letter: J
Question
John Isaac Inc., a designer and installer of industrial signs, employs 60 people. The company recorded the type of the most recent visit to a doctor by each employee. A national assessment conducted in 2014 found that 43% of all physician visits were to primary care physicians, 24% to medical specialists, 24% to surgical specialists and 9% to emergency departments. Test at the 0.02 significance level if Isaac employees differ significantly from the survey distribution.
Here are their results:
Visit Type Number of Visits
Primary care 32
Medical specialist 8
Surgical specialist 14
Emergency 6
State the decision rule. Use 0.02 significance level. (Round your answers to 3 decimal places.)
H0: The employee visits do not differ from the survey distribution.
H1: The employee visits differ from the survey distribution. Reject H0 if X^2 >
Compute the value of chi-square. (Round your answer to 2 decimal places.)
X^2 =
What is your decision regarding H0? REJECT/DO NOT REJECT H0 .
Isaac employees DIFFER/DO NOT DIFFER significantly from the survey distribution.
Explanation / Answer
John Isaac Inc., a designer and installer of industrial signs, employs 60 people. The company recorded the type of the most recent visit to a doctor by each employee. A national assessment conducted in 2014 found that 43% of all physician visits were to primary care physicians, 24% to medical specialists, 24% to surgical specialists and 9% to emergency departments. Test at the 0.02 significance level if Isaac employees differ significantly from the survey distribution.
Here are their results:
Visit Type Number of Visits
Primary care 32
Medical specialist 8
Surgical specialist 14
Emergency 6
State the decision rule. Use 0.02 significance level. (Round your answers to 3 decimal places.)
Table value at 0.02 level =9.837
If the calculated test value > 9.837, reject the null hypothesis.
Reject H0 if X^2 > 9.837
H0: The employee visits do not differ from the survey distribution.
H1: The employee visits differ from the survey distribution. Reject H0 if X^2 >
Compute the value of chi-square.
Goodness of Fit Test
observed
expected
O - E
(O - E)² / E
32
25.800
6.200
1.490
8
14.400
-6.400
2.844
14
14.400
-0.400
0.011
6
5.400
0.600
0.067
60
60.000
0.000
4.412
4.41
chi-square
3
df
.2203
p-value
(Round your answer to 2 decimal places.)
X^2 = 4.41
What is your decision regarding H0?
DO NOT REJECT H0 .
Isaac employees DO NOT DIFFER significantly from the survey distribution.
Goodness of Fit Test
observed
expected
O - E
(O - E)² / E
32
25.800
6.200
1.490
8
14.400
-6.400
2.844
14
14.400
-0.400
0.011
6
5.400
0.600
0.067
60
60.000
0.000
4.412
4.41
chi-square
3
df
.2203
p-value
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