A recent national survey found that high school students watched an average (mea

Question

A recent national survey found that high school students watched an average (mean) of 7.1 DVDs per month with a population standard deviation of 1.00 hour. The distribution of DVDs watched per month follows the normal distribution. A random sample of 33 college students revealed that the mean number of DVDs watched last month was 6.20. At the 0.05 significance level, can we conclude that college students watch fewer DVDs a month than high school students?

3.

Required information

H0: 7.1 ; H1: > 7.1

H0: = 7.1 ; H1: 7.1

H0: 7.1 ; H1: < 7.1

H0: > 7.1 ; H1: = 7.1

4.

Required information

Reject H1 if z < -1.645

Reject H0 if z > -1.645

Reject H1 if z > -1.645

Reject H0 if z < -1.645

5.

Required information

Compute the value of the test statistic. (Negative amount should be indicated by a minus sign.Round your answer to 2 decimal places.)

6.

Required information

Reject H0

Cannot reject H0

7.

Required information

A recent national survey found that high school students watched an average (mean) of 7.1 DVDs per month with a population standard deviation of 1.00 hour. The distribution of DVDs watched per month follows the normal distribution. A random sample of 33 college students revealed that the mean number of DVDs watched last month was 6.20. At the 0.05 significance level, can we conclude that college students watch fewer DVDs a month than high school students?

Explanation / Answer

a) H0: The college students watch not fewer DVDs a month than high school students

   i.e. H0: 7.1

H1: The college students watch fewer DVDs a month than high school students

      ie. H1: < 7.1

b) Decision Rule : Reject H0 if z < -1.645

c) Test Statistic value -5.17

d) Test statistic value (-5.17) < critical value (-1.645). Therefore we reject H0.

The college students watch fewer DVDs a month than high school students.

e) P-Value = 0.0000 closed to 0. so again we reject H0

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