Given a standardized normal distribution (with a mean of 0 and a standard deviat

Question

Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d) below.

Click here to view page 1 of the cumulative standardized normal distribution table.

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a. What is the probability that Z is between

negative 1.551.55

and

1.881.88?

The probability that Z is between

negative 1.551.55

and

1.881.88

is

nothing.

(Round to four decimal places as needed.)

Explanation / Answer

Normal Distribution
Mean ( u ) =0
Standard Deviation ( sd )=1
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
a)
To find P(a < = Z < = b) = F(b) - F(a)
P(X < -1.55) = (-1.55-0)/1
= -1.55/1 = -1.55
= P ( Z <-1.55) From Standard Normal Table
= 0.06057
P(X < 1.88) = (1.88-0)/1
= 1.88/1 = 1.88
= P ( Z <1.88) From Standard Normal Table
= 0.96995
P(-1.55 < X < 1.88) = 0.96995-0.06057 = 0.9094  

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