Four women’s college basketball teams are participating in a single-elimination

Question

Four women’s college basketball teams are participating in a single-elimination holiday basketball tournament. If one team is favored in its semifinal match by odds of 1.95 to 1.05 and another squad is favored in its contest by odds of 2.75 to 1.25, what is the probability that:

Four women’s college basketball teams are participating in a single-elimination holiday basketball tournament. If one team is favored in its semifinal match by odds of 1.95 to 1.05 and another squad is favored in its contest by odds of 2.75 to 1.25, what is the probability that:

Explanation / Answer

Here, the probability that the favored teams win their games is

P1 = 1.95/(1.95+1.05) = 0.65
P2 = 2.75/(2.75+1.25) = 0.6875

a)

Thus,

P(both win) = 0.65*0.6875 = 0.446875 = 0.4469 [ANSWR]

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b)

P(neither win) = (1-0.65)*(1-0.6875) = 0.1094 [ANSWER]

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C)

P(At least one win) = 1 - P(neither win) = 0.8906 [ANSWER]

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