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Public Policy and Political Science. Recent national elections suggest that the

ID: 3376807 • Letter: P

Question

Public Policy and Political Science. Recent national elections suggest that the political ideology of adults in the United States is very evenly divided. In a USA Today/Gallup survey, 29% were Republicans, 30% were Democrats, and 41% were Independents. In addition, 51% of all Republicans, 16% of all Democrats, and 28% of all Independents describe their political views as conservative. Suppose an adult in the United States is selected at random.

(a) What is the probability (± 0.0001) that the adult is a Republican and describes her political views as conservative?

P(RC) =

(b) What is the probability (± 0.0001) that the adult is a Democrat and describes his political views as conservative?

P(DC) =

(c) Suppose the adult described his views as conservative.

What is the probability (± 0.0001) that he is an Independent?

P(I|C) =

Marketing and Consumer Behavior. Americans drink a lot of coffee, and they put all sorts of extras into their coffee to enhance the drink, including flavor shots and flavored creams. Research data indicates that 62% of all coffee drinkers put creamer in their coffee. Of those people who use creamer, 40% say they would drink more coffee if their preferred flavors were offered.

Suppose a coffee drinker is selected at random

(a) Suppose the coffee drinker uses creamer. What is the probability (± 0.0001) hat he would not drink more even if his preferred flavor were offered?

P(M|C) =

(b) What is the probability (± 0.0001) that the coffee drinker uses creamer and would drink more if his preferred flavor were offered?

P(CM) =

(c) Suppose three coffee drinkers are selected at random. What is the probability (± 0.0001) that exactly one uses creamer?

P(1 of 3 uses creamer) =

8.

Public Policy and Political Science. Recent national elections suggest that the political ideology of adults in the United States is very evenly divided. In a USA Today/Gallup survey, 29% were Republicans, 30% were Democrats, and 41% were Independents. In addition, 51% of all Republicans, 16% of all Democrats, and 28% of all Independents describe their political views as conservative. Suppose an adult in the United States is selected at random.

(a) What is the probability (± 0.0001) that the adult is a Republican and describes her political views as conservative?

P(RC) =

(b) What is the probability (± 0.0001) that the adult is a Democrat and describes his political views as conservative?

P(DC) =

(c) Suppose the adult described his views as conservative.

What is the probability (± 0.0001) that he is an Independent?

P(I|C) =

10.

Marketing and Consumer Behavior. Americans drink a lot of coffee, and they put all sorts of extras into their coffee to enhance the drink, including flavor shots and flavored creams. Research data indicates that 62% of all coffee drinkers put creamer in their coffee. Of those people who use creamer, 40% say they would drink more coffee if their preferred flavors were offered.

Suppose a coffee drinker is selected at random

(a) Suppose the coffee drinker uses creamer. What is the probability (± 0.0001) hat he would not drink more even if his preferred flavor were offered?

P(M|C) =

(b) What is the probability (± 0.0001) that the coffee drinker uses creamer and would drink more if his preferred flavor were offered?

P(CM) =

(c) Suppose three coffee drinkers are selected at random. What is the probability (± 0.0001) that exactly one uses creamer?

P(1 of 3 uses creamer) =

Explanation / Answer

the probability (± 0.0001) that the adult is a Republican and describes her political views as conservative

= P(R intersection C)

= P(R)P(C)
= 0.29(0.51)

= 0.1479

---------------------------------------------

b) the probability (± 0.0001) that the adult is a Democrat and describes his political views as conservative

= P(DC) =

= 0.30(0.16)

= 0.048

c) P(I/C) = P(IC)/P(C) = 0.41(0.28)/(0.29)(0.51)+0.30(0.16)+0.41(0.28)

= 0.3695

--------------------------------

a) P(M'/C) = P(M'C)/P(C)

= 60%(62%)/(60%(62%)+(62%)(40%)

= 0.60

b) P(CM) = 0.4(0.62)

=0.248

c) No of coffee drinkers who uses creamer is binomial with p = 0.4 and n =3

P(X=1) = 3C1(0.4)(0.6)2

= 3(0.4)(0.36)

=0.0432

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