need help with #3 please 2. Tree Diagram Problem:.. You do business with Contrac
ID: 3376224 • Letter: N
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need help with #3 please
2. Tree Diagram Problem:.. You do business with Contractor # 1 65% of the time. You do business with Contractor # 2 35% of the time. Contractor # 1 sends bad shipments 5 % of the time Contractor # 2 sends bad shipments 10 % of the time. 1. Probability that Contractor # 1 sends a good shipment. 2. Probability that Contractor # 1 sends a bad shipment. Probability that Contractor # 2 sends a good shipment. 4. Probability that Contractor # 2 sends a bad shipment. 5. Probability that a shipment is good and it came from Contractor # 1. 6. Probability that a shipment is bad and it came from Contractor # 1. 7. Probability that a shipment is good and it came from Contractor # 2. 3. 8. Probability that a shipment is bad and it came from Contractor # 2 Probability that any shipment is good. 10. Probability that any shipment is bad. 11.You are looking at a good shipment-Probability it came from Contractor #1 ? 12. You are looking at a good shipment-Probability it came from Contractor #2 ? 13. You are looking at a bad shipment-Probability it came from Contractor #1 ? 9. 14, You are looking at a bad shipment-Probability it came from Contractor #2 ? 3. You are in the distribution yard where items are being prepared for packaging and Shipping. However, before these items are sent, a final quality control check is required. Fronn experience, it is determined that 15% of the items will not pass quality control. You check the next 50 items. Of these, 16 are determined to be "bad." Is this unusually high? Use the mean and standard deviation to make your argument. Assume that one item's condition has nothing to do with another's.Explanation / Answer
Question 3
Pr(Defective item) = 0.15
Total number of items to be checked = 50
Total bad items = 16
Here expected number of items to be found defective = 50 * 0.15 = 7.5
Standard deviation of items to be found defective out of 50 = sqrt (0.15 * 0.85 * 50) = 2.525
The uppper limit of being unusual number of defective items are = 7.5 + 2 * 2.525 = 12.55
so here 16 > 12.55 so we would sa that it is unusual to find 16 of the items defectiv from a lot of 50.
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