The television show Law & Disorder has been successful for many years. That show

Question

The television show Law & Disorder has been successful for many years. That show recently had a share of 25, meaning that among the TV sets in use, 25% were tuned to Law & Disorder. Assume that an advertiser wants to verify that 25% share value by conducting its own survey, and a pilot survey begins with 13 households have TV sets in use at the time of a Law & Disorder broadcast. Find the probability that none of the households are tuned to Law & Disorder. P(none) = Find the probability that at least one household is tuned to Law & Disorder. P(at least one) = Find the probability that at most one household is tuned to Law & Disorder. P(at most one) = If at most one household is tuned to Law & Disorder, does it appear that the 25% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Law & Disorder unusual?) yes, it is wrong no, it is not wrong

Explanation / Answer

Ans:

Given that

n=13,p=0.25

P(none)=(1-0.25)^13=0.0238

P(atleat one)=1-0.0238=0.9762

P(atmost one)=P(x<=1)=P(x=0)+P(x=1)

=0.0238+13C1*0.251*0.7512

=0.0238+0.1029=0.1267

No,it is not wrong(it is usual,as P(atmost one)>0.05)

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