1. An independent-measures research study uses two samples, each with n = 12, to

Question

1. An independent-measures research study uses two samples, each with n = 12, to compare two treatments. If the results are evaluated with a t statistic using a one-tailed test with ? = .01, then the critical region would have the following boundary:
t = 2.819, t = 2.797, t = 2.492, or t = 2.508 ?

2. An independent-measures research study with n = 6 subjects in each treatment has SS = 70 for treatment 1 and SS = 50 for treatment 2. For these data, the estimated standard error for sample mean differences equals the following:
120, 12, 4, or 2 ?

3. In an independent-measures t hypothesis test, if the samples sizes are large and the variance is very small, then it is possible to obtain a significant difference between treatments even if the actual mean difference is small.
True or False ?

4. If the null hypothesis for a goodness-of-fit test predicts no preference, then the researcher should select a sample with an equal number of individuals in each category
True or False ?

Explanation / Answer

1. Correct answer : - t = 2.819

Reason : t(alpha,n1+n2-2) = t(0.01, 12+12-2) = t (0.01,22) = 2.819

2. Correct answer :- 2

Reason : S2 =( SS1 + SS2 )/(n1+n2-2) = (70+50)/(6+6-2) = 12

Standard error = sqrt(S2((1/n1)+(1/n2))) = sqrt(12/3) = sqrt(4) = 2

3. Correct answer :- True

Reason : Assuming that all other factors have been considered, it is rational to use t-test for even large sample, because the population variance is unknown for almost all cases in practice. When we use sample variance for population variance, we deal with t distribution. This is right philosophically.

4. Correct answer :- True

Reason : In case of 'No preference' in goodness of fit, we use equal proportions among the categories.

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