Data was collected on how much 8 customers recently spent for lunch at Benny\'s

Question

Data was collected on how much 8 customers recently spent for lunch at Benny's Café; see the Excel descriptive statistics file below. 1. After Joey viewed this data, he said "Wow, look how skewed this data is, what with the mean amount spent of $7.38 being so much larger than the standard deviation of $1.57." Clearly state why you do or why you don't agree with Joey's statement. 2. Joey continues... "This data set is really crazy, why look at all of those data outliers with the negative signs." Clearly state why you do or why you don't agree with Joey's statement. Lunch Costs at Benny's Café scores Lunch Cost Count Skewness 0.02258 0.65134 2.08467 -1.4974 0.90666 1-0.9691 0.02817 -0.5935 Mean 7.3825 Skewness Std Error 5.03 Mean LCL 6.06905 Kurtosis 69595 Kurtosis Std Error 2.46828 Skewness (Fisher's) 7.38 Standard Deviation 1.57108 Kurtosis (Fisher's) 5.86 Mean UCL 6.45 Variance 0.52218-0.0016 ean Std Error 0.55546 Coefficient of Variation 0.21281 0.1002 7.54 Mean Deviation 1.2025 0.6858 5.03

Explanation / Answer

Result:

1).

I do not agree with the joey’s statement. To check for skewnee of the data we have to look for skewness. In the data skewness is 0.02258 which is close to 0. The data are not skewed.

2).

I do not agree with the statement. The negative z values implies that corresponding x values are smaller than mean score. If the z values are greater than 2( sometimes 3) or lesser than -2 ( sometimes   -3), then only we can say those values are outliers.

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