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Given the piecewise function defined below and its graph determine the following

ID: 3373344 • Letter: G

Question

Given the piecewise function defined below and its graph determine the following.



a) Does the limit of this function exist as x approaches -2? Why or Why Not? If so, what is it?

b) Is this graph continuous at -2? Why or Why not? If it is not continuous what exists in the graph at x = -2?

c) Does the limit of this graph exist as x approaches zero? Why or Why Not?

d) Is this graph continuous at 4? Why or Why not?

e) What is the limit of this function as x approaches 4 from the left? How about the right? What exists in the graph at x = 4?

f) Does there appear to be a limit as x approaches positive infinity? If so, what is it? What exists in the graph as x approaches infinity?

g) g) Using set notation describe where this graph is continuous.


Given the piecewise function defined below and its graph determine the following.

Explanation / Answer

a) limit of this function does not exist as x approaches -2 because value of function at x=-2(value at x=-2 is 2) is not equal to value of function as x approches -2(value is 9)

b)Graph is not continuous at -2 because value of function at x=-2(value at x=-2 is 2) is not equal to value of function as x approches -2(value is 9) .Removable discontinuity exists

c) limit of this graph exist as x approaches zero because value of function at x=0(value at x=0 is 0) is equal to value of function as x approches 0 from both sides(value is 0)

d)graph is not continuous at 4 because f(4) is undefined [denominator is x-4 and denominator cannot be 0]

e) limit of this function as x approaches 4 from the left is -infinite and limit of this function as x approaches 4 from the right is +infinite.Asymptotic discontinuity[also called essential discontinuity) exists here.

f)limit as x approaches positive infinity is 1.Removable discontinuity exists here.

g)[-infinte,-2)U(-2,4)U(4,infinite)

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