Please see the attached image for the problem: where m is the mass, g is the gra

Question

Please see the attached image for the problem:

where m is the mass, g is the gravitational acceleration, k is the friction coefficient. At the initial moment t = 0 the sky-diver is at rest, v(0) = 0. Derive a differential equation for the acceleration of the sky-diver a(t). Solve the equation in general form, that is derive a formula (using the given symbols) for the acceleration versus time. Sketch the solution indicating the initial value for a (again, through the given symbols). From your sketch, what is the practical value of the acceleration after long time?

Explanation / Answer

a): y?=ky then its y=Ce^kd

b): I am guessing for when

d=0 the intensity that is absorbed is 0 thus meaning C=1

0.50=1ed(10)?d=ln|0.5|10

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