vcluia Reid7/1/18 8:53 PM Time Limit: 02:00:00 Submit Test This Test: 100 pts po

Question

vcluia Reid7/1/18 8:53 PM Time Limit: 02:00:00 Submit Test This Test: 100 pts possible St Test: Exam- Midterm This Question: 7 pts 15or 17 (0 complete) A landscaping company provides yard care services for customers. The company owne tracked the time his following sample data, in minutes, were recorded employees spent at a sample of customer locations The 27 41 22 36 25 36 48 2718 30p 26 20 31 2846 22 29 274426 Describe the central tendency of these data by computing the mean median, and mode Based an thase measures, can you spent Grade at customer locations is skewed or symmetric? The mean is ? (Round to the nearest hundredth as needed) The median is?(Round to the nearest hundredth as needed) ts ss rary ons The mode is[] see sco Round to the nearest hundrecth as needed Use a comma to separate answersa Detormine whether the dstribution of time s heved The distribution is or Enter your answer in each of the answer boses

Explanation / Answer

Mean = (27 + 41 + 22 + .......+ 26) / 20 = 609 / 20 = 30.45

Median = Average of two middle terms for magnitude of the data

Here ascending order of the data(magnitude) : 18,20,22,22,25,26,26,27,27,27,28,29,30,31,36,36,41,44,46,48

In this case 10th and 11th terms are 27 and 28

So Median = (27 + 28) / 2 = 27.50

Mode is Most frquency term in the data

In this case, most frequent term is 27

So Mode = 27.00

In this data, Mean and median and mode are not equal

So data is skewed

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