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This Question: 7 pts 14 of 25 (0 complete)> This Test: 100 pts possible Decide w

ID: 3371023 • Letter: T

Question

This Question: 7 pts 14 of 25 (0 complete)> This Test: 100 pts possible Decide whether the normal sampling distribution can be used. If it can be used, test he claim about the population proportion p at te g en level of significance ? using the given sample statistics. Claim: p s 0.45; ?-0.05; Sample statistics: p-0.44, n-150 Can the normal sampling distribution be used? 0 A. No, because ng is less than 5. O B. Yes, because pq is greater than ? = 0.05. ° C. No, because np is less than 5. D. Yes, because both np and nq are greater than or equal to 5 State the null and alternative hypotheses. A. Ho'?-0.45 Ha: p #0.45 O B. Ho: p 20.45 H. p0.45 Ha p>0.45 D. Determine the critical value(s). Select the correct choice below and, if necessary, fill in the answer box to complete your choice O A. The test cannot be performed. The critical value(s) is/are Round to two decimal places as needed. Use a comma to separate answers as needed.) B. The test cannot be performed

Explanation / Answer

p(hat)= 0.44

n= 150

H0: P <=0.45

H1: P > 0.45..................... right tail test

alpha= 0.05 critical value Z=1.645

Test Statistics

Z= (p(hat)-P)/sqrt(p*q/n)

=(0.44-0.45)/sqrt(0.45*0.55/150)

= -0.24618

P-value=1-P(Z<-0.24618))=0.5972

rounded p-value= 0.5972

Decision making

P-value > Alpha Fail to Reject H0

0.5972>0.05 Fail to reject H0

there is not enough evidence to support the claim that population proportion is less than 0.45.

.................................

answers

D) Yes, both np and nq are greater than or equal to 5.

C )H0: P<= 0.45

H1: P> 0.45

A) critical value is z=Z=1.65

A) Z test =-0.25

B) Fail to reject H0, the data do not provide sufficient evidence to reject the claim.

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