Suppose adults in a particular town drive a mean of 45 mph with a standard devia

Question

Suppose adults in a particular town drive a mean of 45 mph with a standard deviation of 5 mph. A local police officer records the speed of a group of n- 64 drivers and computes the average speed for the group to be M-46.5 mph. A. What is the expected value of M for the sampling distribution of all possible drivers? (Report answer to 1 decimal place.) B. What is the standard error of M for the sampling distribution of all possible drivers? (Report answer to 2 decimal places.) C. How likely is it to obtain a random sample of n 64 drivers with an average speed equal to or greater than 46.5? (Report proportion to 4 decimal places or percentage to 2 decimal places.) D. This score would be considered a(n) (representative/extreme) score because the value of it's z-score is (Report answer to 2 decimal places.)

Explanation / Answer

a)

expected value of M =45

b)

std errror of M=5/sqrt(64)=0.63

c)

P(Xbar>46.5)=P(Z>(46.5-45)/0.63)=P(Z>2.38)=0.0087(please try 0.0082 if this comes wrong)

d)

extreme ; because the value of its z score is 2.38 ( please try 2.40 if this comes wrong)

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.