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The shear strength of each of ten test spot welds is determined, yielding the fo

ID: 3369357 • Letter: T

Question

The shear strength of each of ten test spot welds is determined, yielding the following data (psi 373 368 409358 375 362 389 32 415 367 (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard devlation of shear strength using the method of maximum likelihood. (Round your answers to two declmal places.) average standard deviation 20.04883 X ps 377.8 psi elds wil have their strengths. Hn whats the th percent enter s of and r? Now use then ariance b Again assuming a normal distribution, estimate the strength value below which 95% of all principle.] (Round your answer to two decimal places.) 88.229xpsi H t: P X S 400 ? 400 ? 0 Round your answer to (c Suppose we decide to examine another test spot weld. Let X-shear strength of the weld. Use the given data to obtain the mle of P X S 400 decimal places.) 0.9999 x our

Explanation / Answer

> x <- c(373,368,409,358,375,362,389,362,415,367);x
[1] 373 368 409 358 375 362 389 362 415 367
a) > mean(x)
[1] 377.8
> sd(x)
[1] 20.05

b) > (qnorm(0.95)*sd(x))+mean(x)
[1] 410.78
c) > pnorm((400-mean(x))/sd(x))
[1] 0.87

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