The accompanying data represent the total travel tax? (in dollars) for a? 3-day
ID: 3368288 • Letter: T
Question
The accompanying data represent the total travel tax? (in dollars) for a? 3-day business trip in
8
randomly selected cities. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts? (a) through? (c) below.
68.32
78.17
69.71
84.22
80.28
87.78
100.43
98.21
LOADING...
Click the icon to view the table of critical? t-values.
?(a) Determine a point estimate for the population mean travel tax.
A point estimate for the population mean travel tax is
?$nothing
.
?(Round to two decimal places as? needed.)
?(b) Construct and interpret a
95
?%
confidence interval for the mean tax paid for a? three-day business trip.
Select the correct choice below and fill in the answer boxes to complete your choice.
?(Round to two decimal places as? needed.)
A.
There is a
nothing
?%
probability that the mean travel tax for all cities is between
?$nothing
and
?$nothing
.
B.
The travel tax is between
?$nothing
and
?$nothing
for
nothing
?%
of all cities.
C.
One can be
nothing
?%
confident that the all cities have a travel tax between
?$nothing
and
?$nothing
.
D.
One can be
nothing
?%
confident that the mean travel tax for all cities is between
?$nothing
and??
?$nothing
.
?(c) What would you recommend to a researcher who wants to increase the precision of the? interval, but does not have access to additional? data?
A.
The researcher could increase the sample mean.
B.
The researcher could decrease the sample standard deviation.
C.
The researcher could increase the level of confidence.
D.
The researcher could decrease the level of confidence.
68.32
Explanation / Answer
SOlution
(a) Point estimate = mean = (68.32+.....+98.21)/8 = 667.12/8 = 83.39
(b) 95% confidence inteterval = (mean +- t0.025,7(s/n0.5))
95% CI = ( 83.39 +- 2.365 (11.839/80.5)) = (73.49,93.29)
One can be 95% confident that the mean travel tax for all cities is between 73.49 and 93.29
(c) option (c) The researcher could increase the level of confidence.
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