In a test of the effectiveness of garlic for lowering? cholesterol, 8181 subject
ID: 3367453 • Letter: I
Question
In a test of the effectiveness of garlic for lowering? cholesterol,
8181
subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes? (before minus? after) in their levels of LDL cholesterol? (in mg/dL) have a mean of
0.90.9
and a standard deviation of
22.322.3.
Use a
0.100.10
significance level to test the claim that with garlic? treatment, the mean change in LDL cholesterol is greater than
00.
What do the results suggest about the effectiveness of the garlic?treatment? Assume that a simple random sample has been selected. Identify the null and alternative? hypotheses, test? statistic, P-value, and state the final conclusion that addresses the original claim.
What are the null and alternative? hypotheses?
A.
Upper H 0H0?:
mu?equals=00
?mg/dL
Upper H 1H1?:
mu?not equals?00
?mg/dL
B.
Upper H 0H0?:
mu?equals=00
?mg/dL
Upper H 1H1?:
mu?less than<00
?mg/dL
C.
Upper H 0H0?:
mu?greater than>00
?mg/dL
Upper H 1H1?:
mu?less than<00
?mg/dL
D.
Upper H 0H0?:
mu?equals=00
?mg/dL
Upper H 1H1?:
mu?greater than>00
?mg/dL
Determine the test statistic.
nothing
?(Round to two decimal places as? needed.)
Determine the? P-value.
nothing
?(Round to three decimal places as? needed.)
State the final conclusion that addresses the original claim.
?
Fail to reject
Reject
Upper H 0H0.
There is
?
sufficient
not sufficient
evidence to conclude that the mean of the population of changes
?
is greater than
equal to
is not
is less than
00.
Click to select your answer(s).
Explanation / Answer
option D is correct for hypothesis.
test statistic=d/(s/sqrt(n))=0.9/(22.3/sqrt(81))=0.36
p value =0.359 ( please try 0.360 if this comes wrong)
Fail to reject H0 .There is not sufficient evidence to conclude that the mean of the population of changes is greater than 0.
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