QUESTION 11 Based on the Central Limit Theorem, the sample mean can be used as a

Question

QUESTION 11

Based on the Central Limit Theorem, the sample mean can be used as a good estimator of the population mean, assuming that the size of the sample is sufficiently large.

True

False

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QUESTION 12

To determine the size of a sample, the standard deviation of the population must be estimated by either taking a plot surveying or by approximating it based on knowledge of the population.

True

False

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QUESTION 13

Suppose 1,600 of 2,000 registered voters sampled said they planned to vote for the Green Party candidate from president. Using a 0.95 degree of confidence, what is the interval estimate for the population proportion (to the nearest tenth of a percent)?

76.5% to 83.5%

69.2% to 86.4%

78.2% to 81.8%

77.7% to 82.3%

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QUESTION 14

The 95 percent confidence interval states that 95 percent of the sample means of a specified sample size select from a population will lie within plus and minus 1.96 standard deviations of the hypothesized population mean.

True

False

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QUESTION 15

It is often not feasible to study the entire population because it is impossible to observe all the items in the population.

True

False

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QUESTION 16

The Central Limit Theorem states that for a sufficiently large sample the sampling distribution of the means of all possible samples of size n generated from the population will be approximately normally distributed with the mean of the sample distribution equal to ?2 and the variance equal to ?2/n

True

False

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QUESTION 17

All possible outcomes of size n are selected from a population and the mean of each sample is determined. What is the mean of the sample means?

Larger than the population mean

Smaller than the population mean

Exactly the same as the population mean

Cannot be estimated in advance

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QUESTION 18

In cluster sampling, a population is divided into subgroups called clusters and a sample is randomly from each cluster.

True

False

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76.5% to 83.5%

69.2% to 86.4%

78.2% to 81.8%

77.7% to 82.3%

Explanation / Answer

Ans:

11)True

12)True

13)sample proportion=1600/2000=0.8

95% confidence interval for p

=0.8+/-1.96*sqrt(0.8*(1-0.8)2000)

=0.8+/0.018

=(0.782,0.818)

or

(78.2% to 81.8%)

14)True

15)True

16)False

17)Option c is correct.

Exactly the same as the population mean

18)True

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