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Secure https:/Ing. ceangage.com/static/nblui/index.htmirnbld-8395388nbNodeld-3232 MINDTAP From Cengge o: Chapter 6 End-of-Chapter Problems Due on jun 17 at 11:59 PM MDT 6. Gravetter/Wallnau/Forzano, Essentials-Chapter 6-End-of-chapter question 9 Aa Aa What proportion of a normal distribution is located between each of the following z-score boundaries? Use the Distributions tool to find out. Standard Normal Distribution Mean 0.0 Standard Deviation 1.0 5000 2500 ?.6745 -0.50 and z +0.50 z-0.85 and z-+0.85 1.60 and z-+1.60 MacBook Pro esc G Search or type URLExplanation / Answer
(1) P(-0.50 <= Z <= 0.50) = P(Z <= 0.50) - P(Z <= -0.50) = 0.3829
(2) P(-0.85 <= Z <= 0.85) = P(Z <= 0.85) - P(Z <= -0.85) = 0.6047
(3) P(-1.60 <= Z <= 1.60) = P(Z <= 1.60) - P(Z <= -1.60) = 0.8904
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