A researcher wants to determine whether high school students who attend an SAT p

Question

A researcher wants to determine whether high school students who attend an SAT preparation course score significantly different on the SAT than students who do not attend the preparation course. For those who do not attend the course, the population mean is 1050 (? = 1050). The 16 students who attend the preparation course average 1150 on the SAT, with a sample standard deviation of 300. On the basis of these data, can the researcher conclude that the preparation course has a significant difference on SAT scores? Set alpha equal to .05.

Calculate the 99% confidence interval. Steps:

Q1: The mean you will use for this calculation is

A. 1050

B. 1150

Q2: What is the new critical value you will use for this calculation?

Q3: As you know, two values will be required to complete the following equation: __________ ? ? ? __________

Q4: Which of the following is a more accurate interpretation of the confidence interval you just computed?

A. We are 99% confident that the scores fall in the interval _____ to _____.

B. We are 99% confident that the average score on the SAT by the students who took the prep course falls in the interval _____ to _____.

C. We are 99% confident that the example above has correct values.

D. We are 99% confident that the difference in SAT scores between the students who took the prep course and the students who did not falls in the interval _____ to _____.

Explanation / Answer

Q1) 1150

Q2) Use Excel functions for critical value

T.INV(0.99+(0.01/2),15)

= 2.947

Q3) 1150-2.947*75 = 929.00

1150+2.947*75 = 1371.00

Q4) We are 99% confident that the average score on the SAT by the students who took the prep course falls in the interval _____ to _____.

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