Apple products have become a household name in America with 51 percent of all ho

Question

Apple products have become a household name in America with 51 percent of all households owning at least one Apple product (CNN, March 19, 2012). The likelihood of owning an Apple product is 61 percent for households with kids and 48 percent for households without kids. Suppose there are 1,200 households in a representative community of which 820 are with kids and the rest are without kids.

What is the probability that a household is with kids and owns an Apple product? (Do not round intermediate calculations. Round your answer to 4 decimal places.)

What is the probability that a household is without kids and does not own an Apple product? (Do not round intermediate calculations. Round your answer to 4 decimal places.)

Apple products have become a household name in America with 51 percent of all households owning at least one Apple product (CNN, March 19, 2012). The likelihood of owning an Apple product is 61 percent for households with kids and 48 percent for households without kids. Suppose there are 1,200 households in a representative community of which 820 are with kids and the rest are without kids.

Explanation / Answer

a) Yes. There are either kids in the household or not. No other options possible

b) P(Ac) = 380/1200 = 0.3167

c) P(Apple | With kids) = 0.61

P(A B) = P(Apple | With kids)*P(With kids) = 0.61*(820/1200) = 0.4168

d) P(B | Ac) = 0.48, P(Bc | Ac) = 1-0.48 = 0.52

P(Ac Bc) = P(Bc | Ac)*P(Ac) = 0.52*(380/1200) = 0.1647

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