Two different tests are used to rate student achievement. Use the z-score to det

Question

Two different tests are used to rate student achievement. Use the z-score to determine which student shows more achievement compared to the average: a student with a score of 1840 on a test with mean of 1518 and standard deviation of 325 or student who has a score of 27.0 on a test with a mean of 21.1 and standard deviation of 4.8? The answer should be in three parts: z score for the 1840 result, a z-score for the 27 result and an a statement as to which student showed more achievement. 0.991, 1.23, the first student shows the better achievement because he had a lower z-score -0.991,-1.23 the second student shows more achievement because he had a lower z-score 0.991, 1.23 the second student shows more achievement becuase he had a higher z-score 0.991, 1.23, the first student because he had a better z-score QUESTION 6 A data set has a mean of 65 and a standard deviation of 6. Determine the z score of 102 and 56 and interpret each z score. 6.17, extremely unusual &-1.5 unusual 91.17 extremely unusual and -1.5 unusual 6.17 (extremenly unusual) and -1.5 (usual) -6.17 (extremely unusual and 1.5 (usual)

Explanation / Answer

a) z for first student is (x-mean)/s =(1840-1518)/325=0.991

z for second student =(27-21.1)/4.8=1.23

the correct answer is A

b) z for 102 is (102-65)/6=6.17

z for 56 is (56-65)/6=-1.5

thus the correct option is C

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.