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Suppose that independent random samples of sizenare taken from two normal popula

ID: 3364597 • Letter: S

Question

Suppose that independent random samples of sizenare taken from two normal populations with known variances 21and 22 are used to test the null hypothesis 12=0 against the alternative hypothesis 12=a. Suppose further that the probabilities of type I and type II errors are to have values and respectively.

Problem 4 Suppose that independent random samples of size n are taken from two normal populations with known variances | and 1 are used to test the null hypothesis 1-12-dg against the alternative hypothesis 1-12 = 5a. Suppose further that the probabilities of type I and type II errors are to have values and respectively. (a) Show that the required sample size is given by n= 06-5a)2 (b) Find the required sample size if ,-9, 2-13, _ 80, a-86, 0.01, and -0.01.

Explanation / Answer

Here as type I error is .

H0 : 1 - 2 = 0

Ha : 1 - 2 = a  

Lets say required sample size = n

so first we have to find the sample mean difference xd  , above which we shall be able to reject the null hypothesis.

xd = 0 + Z sqrt (12/n)

Here, if type II error is so that means we cannot reject the null hypothesis even if it is true, that means if sample mean difference woulde be less than xd , then we cannot reject the null hypothesis.

so,

xd = a   - Z (22/n)

so comparing both values.

0 + Z sqrt (12/n) = a   - Z (22/n)

n = (12 + 22( (Z + Z)2/ (0 - a)2

(b) Here 1  = 9 ; 2  = 13 ; 0  = 80 ; a   = 86

Z = Z0.005 = 2.575 ;  Z   = Z0.01 = 2.326

n = (12 + 22) (Z + Z)2/ (0 - a)2

n = (92 + 132) * (2.575 + 2.326)2 /(86 - 80)2

n = 250 * 24.02 / 36 = 166.81

n = 167

so n could be 167.

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