QUESTION9 The data table below contains the amounts that a sample of nine custom
ID: 3364542 • Letter: Q
Question
QUESTION9 The data table below contains the amounts that a sample of nine customers spent for lunch (in 4.22 5.01 5.82 6.52 7.33 7.42 8.61 8.46 9.73 Is there any evidence that the mean amount spent for lunch is different from $6.50 Using the table below calculate the STAT dollars) at a fast Descriptive Statistics Mean 7.013333 0.59828 7.33 Standard Error Median Mode Standard Deviation 1.79484 Sample Variance 3.2214 Kurtosis Skewness Range Minimum Maximum Sum Count HN/A -0.84277 0.12253 5.51 4.22 9.73 63.12 0.9023 0.8580 0.8660 0.9053Explanation / Answer
Below are the null and alternate hypothesis
H0: mu = 6.5
H1: mu not equals 6.5
Test statistics, t = (xbar - mu)/SE
t = (7.0133 - 6.5)/(1.79484/sqrt(9))
t = 0.8580
Option B is correct
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