(%) 5.4.14 Assigned Media | Question Help In a clinical trial of a drug used to
ID: 3364364 • Letter: #
Question
(%) 5.4.14 Assigned Media | Question Help In a clinical trial of a drug used to help subjects stop smoking, 816 subjects were treated with 1 mg doses of the drug. That group consisted of 41 subjects who experienced nausea. The probaby of nausea for subjects not receiving the treatment was 0.0115. Complete parts (a) through (c). a. Assuming that the drug has no effect, so that the probability of nausea was 0.0115, find the mean and standard deviation for the numbers of people in groups of 816 that can be expected to experience nausea The mean ispeople. (Round to one decimal place as needed.)Explanation / Answer
Solution:-
5.4.14 problem
a) Given n=816, p=0.0115
=> mean = n*p = 816*0.0115 = 9.384 = 9.4(rounded)
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Solution:-
a) Given n=819, p=0.0142
=> mean = n*p = 819*0.0142 = 11.6298 = 11.6(rounded)
=> standard deviation=n*p*(1-p)
= sqrt( 819*0.0142*(1-0.0142))
= 3.3859
= 3.4 (rounded)
=> Second part asnwer was right .
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