A candy company claims that 23% of its plain candies are orange, and a sample of
ID: 3364244 • Letter: A
Question
A candy company claims that 23% of its plain candies are orange, and a sample of 200 such candies is randomly selected.
a. Find the mean and standard deviation for the number of orange candies in such groups of 200.
=
=
b. A random sample of 200 candies contains 64 orange candies. Is this result unusual? Does it seem that the claimed rate of 23% is wrong?
A.Yes comma because 64 is greater than the maximum usual value.Yes, because 64 is greater than the maximum usual value.Thus, the claimed rate of 23% is
probably wrong.
B.No, because 64 is within the range of usual values Thus, the claimed rate of 23% is not necessarilynot necessarily wrong.
C. Yes, because 64 is below the minimum usual value. Thus, the claimed rate of 23% is not necessarily wrong.
D. Yes, because 64 is within the range of usual values. Thus, the claimed rate of 23% is probably wrong.
Explanation / Answer
a. p = 0.23
n = 200
= 200 * 0.23 = 46
= (46 * 0.77) = 5.9515
b. s = 64
z = (64 - 46) / 5.9515
= 3.024
P(z > 3.024) = 0.0012 < 0.05
The answer is :
A.Yes comma because 64 is greater than the maximum usual value.Thus, the claimed rate of 23% is probably wrong.
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