1. If a person is randomly selected, find the probability that his or her birthd
ID: 3363920 • Letter: 1
Question
1. If a person is randomly selected, find the probability that his or her birthday is in December. Ignore leap years.
A. 1/31
B. 1/365
C. 1/12
D. 31/365
----------------------------------------------------------------------------------------
2. In a poll, respondents were asked whether they had ever been in a car accident. 204 respondents indicated that they had been in a car accident and 365 respondents said they had not been in a car accident. If one of these respondents is randomly selected, what is the probability of getting someone who has been in a car accident? Round to the nearest thousandth, if necessary.
A. 0.559
B. 0.359
C. 0.641
D. 0.005
------------------------------------------------------------------------------
3. Suppose you randomly select a family with three children. Assume that births of boys and girls are equally likely. What is the probability that the family has at least one boy?
A. 0.125
B. 0.75
C. 0.857
D. 0.875
---------------------------------------------------------------------------
4. Two 6-sided dice are rolled. What is the probability that the sum of the two numbers on the dice will be 3?
A. ½
B. 2
C. 1/18
D. 17/18
Explanation / Answer
1) Total number of months = 12
So, P(birthday is in December) = 1/12 (option C)
2) P(respondent has been in a car accident) = number of people who had been in car accident / total number of respondents
= 365/(365+304)
= 0.641 (option C)
3) P(at least 1 boy) = 1 - P(all girls)
= 1 - 0.53
= 0.875 (option D)
4) total number of outcomes = 36
Number of outcomes with sum 3 = 2 {(1,2)(2,1)}
P(sum = 3) = 2/36
= 1/18 (option C)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.