Also asking for the amount of hours at the 10th unit for Julie Providence Assess

Question

Also asking for the amount of hours at the 10th unit for Julie

Providence Assessment Center screens and trains employees for a computer assembly firm in Boston. The progress of all trainees is tracked and those not showing the proper progress are moved to less demanding programs. By the tenth repetition trainees must be able to complete the assembly task in 1 hour or less. Susan Sweaney has just spent 7 hours on the fourth unit and 5 hours completing her eighth unit, while another trainee, Julie Burgmeier, took 3 hours on the third and 2 hours on the sixth unit. Time required by Susan for the tenth unit: (Note: You must round all intermediate calculations to at least three decimal places before proceeding with subsequent calculations.) 10th unit hours (round your response to two decimal places).

Explanation / Answer

We have to first determine Learning rate for both persons.

Learning Rate can be described in terms of percentage and fraction.

Thus , when the quantity doubles , the time taken to perform the doubled unit becomes Learning rate( %) /100 x Initial unit

‘Thus , if Susan has spent 7 hours on the 4th unit and 5 hours for the 8th unit , Learning rate = 5/7 x 100 = 71.43%

Similarly, if Julie took 3 hours on the third and 2 hours on the sixth unit , Learning rate = 2/3 x 100 = 66.67%

We will use Standard learning curve table and Learning rate of 71.43 % of Susan to derive:

Accordingly,

Time required by Susan for the first unit = 13.72 hours

Time required for the 10th unit = 4.49 hours

We will use Standard learning curve table and Learning rate of 66.47 % of Julie to derive:

Accordingly,

Time required by Julie for the first unit = 5.70 hours

Time required for the 10th unit = 1.48 hours

TIME REQUIRED BY SUSAN FOR 10TH UNIT = 4.49 HOURS

TIME REQUIRED BY JULIE FOR 10TH UNIT = 1.48 HOURS

TIME REQUIRED BY SUSAN FOR 10TH UNIT = 4.49 HOURS

TIME REQUIRED BY JULIE FOR 10TH UNIT = 1.48 HOURS

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