How do rented housing units differ from units occupied by their owners? Here are

Question

How do rented housing units differ from units occupied by their owners? Here are the distributions of the number of rooms for owner-occupied units and renter occupied units in San Jose, California.

Find the standard deviation for both distributions. The standard deviation provides a numerical measure of spread.

Rented:

Owend:

thank

you for the help!

Rooms 1 2 3 4 5 6 7 8 9 10 Owned 0.003 0.002 0.023 0.102 0.214 0.225 0.194 0.149 0.053 0.035 Rented 0.008 0.027 0.287 0.376 0.155 0.097 0.031 0.013 0.003 0.003 ra as e test of a generic sada versus brand narne soda, 30% o tasters can distinguish between the co as.45 asters are asked to take the aste test and guess which cup contains the brand name soda the tasars do not Interact wth each ather during the test he es , are don e independently in separate locations, so that (a)The count uf corect guesses in 45 taste tests has a Binomial distribution. What ere and p? (b) Vtiat is the nean nurnber of correct yuesses in ndriy repetitionis? BR , what is the probability of xactly 11 correct guesses?

Explanation / Answer

In R you can find the standard devitions by sd(x)

Here is the code:

Owned <- c(0.003, 0.002 ,0.023, 0.102, 0.214, 0.225, 0.194 ,0.149, 0.053 ,0.035)

Rented <- c (0.008, 0.027 ,0.287, 0.376, 0.155 ,0.097, 0.031, 0.013 ,0.003, 0.003)

print(Owned)

print(Rented)

sd(Rented)

sd(Owned)

Output:

sd(Rented)
0.1329662

sd(Owned)
0.08896816

SOlution2:

Binomial distr

n=45

p=prob of success=30%=0.3

SOlutionb:

mean=np

=45*0.3

=13.5

Solutionc:

P(X=11)

n=45

p=0.3

x=11

P(X=x)=ncxp^xq^n-x

=45C11(0.3)11  (1-0.3)45-11

=0.0973

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