1) Suppose P(C) =0 .048, P(M and C) = 0.044, and P(M or C) = 0.524. Find the ind
ID: 3362929 • Letter: 1
Question
1) Suppose P(C) =0 .048, P(M and C) = 0.044, and P(M or C) = 0.524. Find the indicated probability. 1) P(M'or C') 2) P(C')
2) if 3 balls are drawn from a bag containing 3 red and 4 blue balls, what is the expected number of red balls in the sample?
3) a family has five children. the probability of having a girl is (1/2). what is the probability of having at least 3 boys?
4) A die is rolled five times and the number of fours that come up is tallied. find the probability of getting exactly five fours
Explanation / Answer
Solution :
Given that ,
P(C) =0 .048, P(M and C) = 0.044, and P(M or C) = 0.524
P(M'or C') = P(M and C)' = 1 - P(M and C) = 1 - 0.044 = 0.956
P(M'or C') = 0.956
P(C') = 1 - P(C) = 1 - 0.048 = 0.952
P(C') = 0.952
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