Score: 0.17 of 1 pt 3of3(3complete) HW Score: 72.22%, 2.17 9.3.5-T Quest on Help

Question

Score: 0.17 of 1 pt 3of3(3complete) HW Score: 72.22%, 2.17 9.3.5-T Quest on Help A shudy was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normaly and d not assume that the population tardard deviatios an eam Cemete pats (a) and (b) bel-Une aasupdena-fr en es a. Test the claim that the two samples are from popuilations with the same mean What are nu and aterrative hypotheses? The test statt, LisRundtotwo decre places as needed) 3 5 3

Explanation / Answer

Given that,
mean(x)=2.38
standard deviation , s.d1=0.83
number(n1)=28
y(mean)=2.62
standard deviation, s.d2 =0.58
number(n2)=33
null, Ho: u1 = u2
alternate, H1: u1 != u2
level of significance, = 0.1
from standard normal table, two tailed t /2 =1.703
since our test is two-tailed
reject Ho, if to < -1.703 OR if to > 1.703
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =2.38-2.62/sqrt((0.6889/28)+(0.3364/33))
to =-1.2866
| to | =1.2866
critical value
the value of |t | with min (n1-1, n2-1) i.e 27 d.f is 1.703
we got |to| = 1.28658 & | t | = 1.703
make decision
hence value of |to | < | t | and here we do not reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != -1.2866 ) = 0.209
hence value of p0.1 < 0.209,here we do not reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 != u2
test statistic: -1.2866
critical value: -1.703 , 1.703
decision: do not reject Ho
p-value: 0.209

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