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WileyPLUS e Chegg Study | Guided S C Secure | https://edugen.wileyplus.com/edugen/student/mainfr.uni : Apps D Twu Home Texas -My Blackboard-Bla Home Q Your Sets Quizlet-. Texas Woman's Uni t 'i Danielle Hardesty T- Chegg Study Guide D WileyPLUS Home d Assignment Open Assignment FULLSCREEN pRIN TER VERSION BACK NEXT ASSIGNMENT RESOURCES Unit 4, Topic 18, Exercise 18-07 Charitable Contributions Unit 4, Topic 18 Unit 4, Topic 1 The 2004 General Social Survey found that 1052 from a random sample of 1334 American adults dlaimed to have made a financial contribution to charity in the previous year Round your answers to three decimal places, if required. Exercise 18-18 a Find a 95 % confidence interval for the proportion of all American households that made a financial contribution to charity in the previous year Exercise 18-22 b. Repeat part a with a 99 % confidence interval Review Result Objective Stu c. Based on these confidence intervals, without carrying out a test of significance, indicate whether or not this sample proportion differs significantly from 0.75 at the -0.01 level This sample from 0.75 at the = 0.01 significance level. d. Based on differs rvals, without doing a test of significance, indicate whether or not this sample proportion differs significantly from 80 % at the =0.05 level. does not differ All Rights Reserved. A Division of Version 4.24.2.4 614 PM 11/15/20172 Type here to search

Explanation / Answer

Solution:

From the given information we have
n = 1334
p = 1052/1334 = 0.789
a) 95% confidence interval is
Z/2 = Z0.05/2 = Z 0.025 = 1.96

C.I = p ± Z/2 *sqrt[p(q-p)/n]
= 0.789 ± 1.96 * sqrt[0.789(1-0.789)/1334]
= 0.789 ± 0.02189
= (0.76711, 0.81089)

b) 99% confidence interval is
Z/2 = Z0.01/2 = Z0.005 = 2.576

C.I = p ± Z/2 *sqrt[p(q-p)/n]
= 0.789 ± 2.576 * sqrt[0.789(1-0.789)/1334]
= 0.789 ± 0.0287
= (0.7603, 0.8177)

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