An experiment was conducted to determined which of three advertiseents to use in

Question

An experiment was conducted to determined which of three advertiseents to use in introducing a new personal computer. A total of 120 people who were thinking of buying a personal computer was split randomly into three groups of 40 each. Each group was shown a different advertisement and each person was asked his or her likelihood of buying the advertised brand. A sacle of 1 (very unlikely) to 7(very likely) was used. the Results showed that the average likelihood of purchase was

Advertisement A: 5.5

Advertisement B: 5.8

Advertisement C: 5.2

The ANOVA table was as follows:

a. What is the F-ratio? The p-value?

b. Is the result significant at the .10 level? The .05 level? The .01 level?

c. Are there any differences among the impacts of the advertisements?

***Please show all work so I can fully understand, thank you

Source of Variation SS df MSS Due to advertisements 12 2 6.0 Unexplained 234 117 2.0 Total 246 119

Explanation / Answer

a) F-ration = 6/2= 3

b)

P-value = 0.05363 which is > alpha 0.05, 0.01, so we accept H0

Thus we conclude that advertisement is not significant

P-value = 0.05363 which is < alpha 0.10, so we reject H0

Thus we conclude that advertisement is significant

c) At alpha = 10% , the advertisement is significant

Source Sum of square df MS F-Ratio P-value Between Group 12 2 6 3 0.053631988 Within Groups 234 117 2 Total 246 119

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