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nthe Internet can contain vinuces. Unles you ned to edit it waler to ntay n Protected Vimabe edting Word have been disabled 20. A simple random sample of size n is drawn. The sample mean, , is found to be 35.1, and the sample standard deviation, s, is found to be 8.7 (a) Construct a 90% confidence interval for if the sample size, (b) Construct a 90% confidence interval for if the sample (c) Construct a 98% confidence interval for if the sample n, is 40 size, n, is 100. How does increasing the sample size affect the margin of error, E? size, n, is 40. Compare the results to those obtained in part (a). How does increasing the level of confidence affect the margin of error. E? Answer Sheet 2023-282 Lab 2 #27 Name

Explanation / Answer

a)

Standard error of the mean = SEM = S/N = 1.376

t(, N-1) = 1.685

Confidence interval = m +/- (t(, N-1)*SEM)

Mean = 35.1

Lower bound: 32.78

Upper bound: 37.42

b)

Mean = 35.1

Lower bound: 33.66

Upper bound: 36.54

The increase in sample size results in decrease of margin of error

c)

Standard error of the mean = SEM = S/N = 1.376

t(, N-1) = 2.426

Confidence interval = m +/- (t(, N-1)*SEM)

Mean = 35.1

Lower bound: 31.76

Upper bound: 38.44

The increase in confidence interval results in increase in of margin of error

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